📚 Review: #1250 - Longest Common Subsequence (1st)

[github-actions]

🔄 1st Review - Spaced Repetition

It's time to review this problem to reinforce your understanding!

📊 Problem Details

• Platform: LEETCODE
• Problem: #1250 - Longest Common Subsequence
• Difficulty: MEDIUM
• Originally Solved: 12/26/2025 (0 days ago)
• Original PR: LeetCode Longest Common Subsequence Problem #111
• Solution File: leetcode/medium/1250-longest-common-subsequence/longest-common-subsequence.ts

📝 Review Instructions

1. Try solving it again without looking at your solution first
2. Compare approaches:
   • Did you solve it the same way?
   • Is your new approach more efficient?
   • What did you remember vs. forget?
3. Comment below with:
   • ✅ "Solved again easily" / "Needed hints" / "Struggled"
   • Any new insights or patterns you noticed
   • Time/space complexity comparison
4. Close this issue when you've completed the review

🧠 Learning Science

This is your 1st review (1 days after solving). Spaced repetition at increasing intervals helps move knowledge from short-term to long-term memory!

📈 Progress Tracking

• Review 1 of 1
• Next review: Final review!

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🔗 Similar Issues

Related Issues

• 📚 Review: #0115 - Distinct Subsequences (1st) #101
• 📚 Review: #0072 - Edit Distance (1st) #97
• 📚 Review: #0115 - Distinct Subsequences (2nd) #109

🔗 Related PRs

#59 - Leetcode Maximum Length of Repeated Subarray [merged]
#95 - LeetCode Edit Distance Problem [merged]
#99 - LeetCode Number of Distinct Subsequences [merged]
#111 - LeetCode Longest Common Subsequence Problem [merged]

👤 Suggested Assignees

• pertrai1

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💬 Have feedback or questions? Drop into our discord!

[pertrai1]

function longestCommonSubsequence(text1: string, text2: string): number {
  const m = text1.length;
  const n = text2.length;
  
  const dp = Array.from({ length: m + 1 }, () => new Array(n + 1).fill(0));
 
  for (let i = 1; i <= m; i++) {
    for (let j = 1; j <= n; j++) {
      if (text1[i - 1] === text2[j - 1]) {
        dp[i][j] = dp[i - 1][j - 1] + 1;
      } else {
        dp[i][j] = Math.max(dp[i - 1][j], dp[i][j - 1]);
      }
    }
  }
  return dp[m][n];
}

"Needed hints"

[github-actions]

✅ Review Completed!

Great work! You've completed review 1 of 5 for #1250 - Longest Common Subsequence.

📊 Progress

██░░░░░░░░ 20%

• ✅ Completed: 1/5 reviews
• 📅 Remaining: 4 review(s)

🔜 Next Review Scheduled

Your next review (Review 2) has been automatically scheduled for 2025-12-30.

The review is spaced based on when you completed this review, ensuring optimal retention intervals even if you're a few days late! 🧠

🧠 Keep Learning

• Continue solving new problems
• Watch for review notifications
• The more you practice with spaced repetition, the stronger your retention!

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Review completion recorded in docs/reviews/review-schedule.json