Time - Emily #43
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Time - Emily #43
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…le palindrome methods.
CheezItMan
reviewed
Apr 24, 2020
CheezItMan
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CheezItMan
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Overall nice work, you hit the learning goals here. I'm glad you could get this in. These types of questions are very common in interviews. Take a look at my inline comments and let me know what questions you have. Mostly my comments involve simplifying code.
| @@ -1,3 +1,20 @@ | |||
| def intersection(list1, list2) | |||
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| if duplicate_letters.values.sum == string_array.length || duplicate_letters.values.sum == string_array.length - 1 | ||
| return true | ||
| else | ||
| return false | ||
| end |
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You can simplify this and eliminate the if statement, since you're looking for a true/false answer.
Suggested change
| if duplicate_letters.values.sum == string_array.length || duplicate_letters.values.sum == string_array.length - 1 | |
| return true | |
| else | |
| return false | |
| end | |
| return duplicate_letters.values.sum == string_array.length || duplicate_letters.values.sum == string_array.length - 1 |
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| if intersections[value] | ||
| intersections[value] += 1 | ||
| end |
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What if the value isn't in intersections? Why not return false, if it's not there.
I would also suggest subtracting instead of adding, and then you can check to see if all the values are 0.
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