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49 changes: 49 additions & 0 deletions khj20006/202510/29 BOJ P1 쉽게 제한된 메모리.md
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```cpp
#include <bits/stdc++.h>
using namespace std;
using ll = long long;

const ll MOD = 1'000'000'007;
ll N, X, A, B, Q, ans = 0, s[100]{}, e[100]{};
vector<int> q, p;

int main() {
cin.tie(0)->sync_with_stdio(0);

cin >> N >> X >> A >> B >> Q;
q.resize(Q);
p.resize(Q);
iota(p.begin(), p.end(), 0);
for (int& i : q) cin >> i, i++;
fill(e, e + Q, MOD - 1);
sort(q.begin(), q.end());

int rem = Q;
while (rem) {
vector<int> ms;
for (int i = 0; i < Q; i++) if (s[i] < e[i]) ms.push_back((s[i] + e[i] + 1) >> 1);
sort(ms.begin(), ms.end());
ms.erase(unique(ms.begin(), ms.end()), ms.end());
vector<int> cnt(ms.size());

int pos = 0;
for (ll x = X, j = 0; j < N - 1; j++) {
int d = upper_bound(ms.begin(), ms.end(), x) - ms.begin();
if (d != ms.size()) cnt[d]++;
x = (x * A + B) % MOD;
}
for (int i = 1; i < ms.size(); i++) cnt[i] += cnt[i - 1];

for (int i = 0; i < Q; i++) if (s[i] < e[i]) {
int m = (s[i] + e[i] + 1) >> 1;
int idx = lower_bound(ms.begin(), ms.end(), m) - ms.begin();
if (cnt[idx] < q[i]) s[i] = m;
else e[i] = m - 1;
if (s[i] >= e[i]) ans += (s[i] + e[i] + 1) >> 1, rem--;
}
}

cout << ans;

}
```