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56 changes: 56 additions & 0 deletions 0224LJH/202510/31 BOJ 다이어트.md
Original file line number Diff line number Diff line change
@@ -0,0 +1,56 @@
```java
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;

public class Main {

static long diff;
static StringBuilder sb = new StringBuilder();


public static void main(String[] args) throws IOException {
init();
process();
print();
}

private static void init() throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));;
diff = Integer.parseInt(br.readLine());
}

private static void process() {

long pre =1l;
boolean isEmpty = true;
for (long i = 2; i <= 500000; i++) {
long num = i*i;
if (num - pre > diff) break;
pre = num;

long target = num - diff;
if (target == 0) continue;
long sqrt = (long) Math.sqrt(target);
if (sqrt*sqrt != target) continue;
isEmpty = false;
sb.append(i).append("\n");



}

if(isEmpty)sb.append("-1");

}



private static void print() {
System.out.println(sb.toString());
}
}


```
30 changes: 30 additions & 0 deletions 0224LJH/202511/03 PGM 뒤에 있는 큰 수 찾기.md
Original file line number Diff line number Diff line change
@@ -0,0 +1,30 @@
```java
import java.io.*;
import java.util.*;

class Solution {
public int[] solution(int[] numbers) {
int n = numbers.length;
int[] answer = new int[n];
Stack<Integer> stack = new Stack<>();

for (int i = n - 1; i >= 0; i--) {
// 현재 원소보다 작거나 같은 스택의 원소들을 제거
while (!stack.isEmpty() && stack.peek() <= numbers[i]) {
stack.pop();
}

if (stack.isEmpty()) {
answer[i] = -1;
} else {
// 스택의 맨 위가 뒷 큰수
answer[i] = stack.peek();
}

stack.push(numbers[i]);
}

return answer;
}
}
```