[20250226] BOJ / 골드3 / 웜홀 / 김수연 #187
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🧷 문제 링크
https://www.acmicpc.net/problem/1865
🧭 풀이 시간
60분
👀 체감 난이도
✏️ 문제 설명
도로와 웜홀이 주어지는데, 웜홀을 통과하면 주어진 시간만큼 시간이 거꾸로 간다.
출발을 하여 다시 출발을 했던 위치로 돌아왔을 때, 출발을 했을 때보다 시간이 되돌아가 있는 경우 구하기
🔍 풀이 방법
음수의 가중치도 존재하기 때문에 벨만-포드 알고리즘을 사용했다.
N-1번 반복하며 각 노드에 도달하기 위한 최소의 시간을 저장해두고, N번째에서 지금까지 저장된 값보다 작은 값이 나온다면 음의 사이클이 존재하는 것이므로, true를 반환했다.
⏳ 회고
벨만-포드 알고리즘을 오랜만에 사용해서 헤맸다..