[20250918] PGM / LV2 / 지게차와 크레인 / 김수연 #923
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🧷 문제 링크
https://school.programmers.co.kr/learn/courses/30/lessons/388353
🧭 풀이 시간
30분
👀 체감 난이도
✏️ 문제 설명
지게차로 창고에서 접근이 가능한 해당 종류의 컨테이너 모두 꺼낸다.
접근이 가능한 컨테이너는 4면 중 적어도 1면이 창고 외부와 연결된 컨테이너를 말함.
알파벳 하나로만 출고 요청이 들어올 경우 -> 접근 가능한 컨테이너를 꺼냄
같은 알파벳이 두 번 반복된 경우 -> 요청된 종류의 모든 컨테이너를 꺼냄
모든 요청 수행한 수 남은 컨테이너 수 구하기
🔍 풀이 방법
request를 하나씩 실행하면서 1번 2번 케이스 분류 후
bfs 알고리즘인 check함수 통해서 접근 가능 여부 확인하고 삭제시킴
⏳ 회고
차근히 풀면된다