Completed BFS-1. Requesting Review

[AnirudhS30]

No description provided.

[super30admin]

Let's evaluate each problem separately.

For problem_1.py (Level Order Traversal):

1. Correctness: The solution correctly implements a BFS approach to traverse the tree level by level, which is the standard approach for this problem.
2. Time Complexity: O(n), where n is the number of nodes in the tree, as each node is visited exactly once.
3. Space Complexity: O(n), as the queue can hold up to n nodes in the worst case (for a perfectly balanced tree).
4. Code Quality: The code is clean and readable. The variable names are appropriate, and the logic is straightforward. One minor improvement could be to use more descriptive variable names like 'current_level' instead of 'level'.
5. Efficiency: The solution is already optimal for this problem.

For problem_2.py (Course Schedule):

1. Correctness: The solution correctly implements Kahn's algorithm for topological sorting to detect cycles in a directed graph, which is the standard approach for this problem.
2. Time Complexity: O(V + E), where V is the number of courses (vertices) and E is the number of prerequisites (edges).
3. Space Complexity: O(V + E), for storing the adjacency list and indegree array.
4. Code Quality: The code is generally good, but could be improved:
   • The variable 'hmap' could be named more descriptively as 'adjacency_list'.
   • The edge processing loop could be simplified using direct iteration over edges.
   • The initial check for empty prerequisites could be moved to the start of the function.
5. Efficiency: The solution is efficient, but the initial check for empty prerequisites might be unnecessary as the algorithm would handle this case correctly anyway.

General suggestions:

• Both solutions could benefit from docstrings explaining the approach.
• Consistent spacing around operators would improve readability (e.g., 'hmap= {}' vs 'hmap = {}').
• The course schedule solution could add a check to verify if numCourses is valid (>= 0).