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The student's solution demonstrates a good understanding of SQL concepts and problem-solving approach. Here's a detailed evaluation:

  1. Correctness:
  • For Market_Analysis_II.sql, the solution correctly identifies users whose second sold item matches their favorite brand. The use of window functions and joins is appropriate.
  • For Tournament_winners.sql, the solution correctly identifies the winner for each group based on total score and player_id tiebreaker. The UNION ALL approach to combine scores is correct.
  1. Time Complexity:
  • Both solutions use window functions (rank() and row_number()) which typically have O(n log n) complexity where n is the number of rows.
  • The joins are efficiently implemented and shouldn't cause performance issues.
  1. Space Complexity:
  • The CTEs create temporary tables in memory, but they're necessary for the solution and don't appear excessive.
  1. Code Quality:
  • Strengths:
    • Good use of CTEs to break down complex logic into manageable parts
    • Proper indentation and formatting
    • Descriptive column and table aliases
  • Areas for improvement:
    • In Market_Analysis_II.sql, the final CASE statement could be simplified to just check if c.user_id is null
    • The column name "2nd_item_fav_brand" should be quoted or renamed to avoid using numbers at the start
    • Consider adding comments to explain complex logic steps
  1. Efficiency:
  • Both solutions are already quite efficient, but for Tournament_winners.sql, the solution could potentially be optimized by combining some CTEs to reduce the number of temporary tables created.

Potential edge cases to consider:

  • Users who haven't sold any items (handled correctly with LEFT JOIN)
  • Users who have only sold one item (handled correctly)
  • Ties in tournament scores (handled correctly with player_id tiebreaker)

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2 participants