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@Feminto Feminto commented Jun 12, 2025

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The student has provided two solutions for the nth_highest_salary problem and one for the second_highest_salary problem. Here's my evaluation:

Strengths:

  1. Correctness: Both implementations correctly handle the problem requirements, including edge cases where N is invalid or there aren't enough unique salaries.
  2. Readability: The code is generally readable with clear variable names and comments explaining the logic.
  3. Edge Cases: Proper handling of edge cases like N being 0, negative, or larger than the number of unique salaries.

Areas for Improvement:

  1. Redundancy: The two methods in NthHighestSalary.py are essentially doing the same thing, with Method 2 being less efficient (using a set and manual iteration). Method 1 is clearly better and Method 2 should be removed.
  2. Efficiency: While both solutions are correct, they could be optimized. The current approach sorts all unique salaries, which is O(n log n) time complexity where n is the number of unique salaries. For large datasets, this might be inefficient if we only need the Nth highest salary.
  3. Code Duplication: The second_highest_salary function could be written as a special case of nth_highest_salary with N=2, reducing code duplication.
  4. Best Practices: The function could use pandas' built-in methods more effectively. For example, nlargest() could be used to potentially improve performance.

Time Complexity:

  • Current solution: O(n log n) due to sorting all unique salaries
  • Space Complexity: O(n) for storing unique salaries

Optimization Suggestions:

  1. Consider using pandas' nlargest() method which might be more efficient for large N.
  2. For very large datasets where you only need one specific rank, a more efficient algorithm could be used that doesn't require sorting all elements.

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