Completed Sql4

Problem1_SeniorJunior.sql

@@ -0,0 +1,19 @@
+# Write your MySQL query statement below
+with cte as
+(select 
+*,
+sum(salary) over (partition by experience order by salary,employee_id) as rsum
+from candidates 
+)
+
+select 
+'Senior' as experience,
+count(employee_id) as accepted_candidates
+from cte
+where experience='Senior' and rsum <= 70000
+union all
+select 'Junior' as experience,
+count(employee_id) as accepted_candidates
+from cte
+where experience ='Junior' 
+and rsum <= (select 70000-coalesce(max(rsum),0) from cte where experience ='Senior' and rsum <= 70000)

Problem2_LeagueStatistics.sql

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+# Write your MySQL query statement below
+with cte as (
+    select home_team_id as 'id',home_team_goals as goal_for,away_team_goals as goal_against
+    from matches 
+    union all
+    select away_team_id as 'id',away_team_goals as goal_for,home_team_goals as goal_against
+    from matches
+)
+
+#select * from cte
+
+select  t.team_name,
+count(c.id) as matches_played,
+sum(case when goal_for > goal_against then 3
+     when goal_for = goal_against then 1
+     else 0 end) as points,
+sum(c.goal_for) as goal_for,
+sum(c.goal_against) as goal_against,
+sum(c.goal_for)- sum(c.goal_against) as goal_diff
+ from cte c
+ inner join Teams t on c.id=t.team_id
+ group by id
+ order by points desc,goal_diff desc,t.team_name 

Problem3_SalesPerson.sql

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+# Write your MySQL query statement below
+
+with cte as
+(select distinct sales_id
+from orders o inner join company c on o.com_id=c.com_id
+where name='RED')
+
+select name
+from salesperson
+where sales_id not in (select sales_id from cte)

Problem4_FriendRequestsII.sql

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+# Write your MySQL query statement below
+with cte as
+(select requester_id as id
+from requestAccepted
+union all 
+select accepter_id as id
+from requestAccepted)
+
+select distinct id,
+count(id) as num
+from cte
+group by id
+order by 2 desc limit 1