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cliRPL supports interactive mode when called with the -i flag. #2

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cliRPL supports interactive mode when called with the -i flag. #2

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33 changes: 26 additions & 7 deletions cliRPL.py
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Original file line number Diff line number Diff line change
Expand Up @@ -33,17 +33,36 @@ def usage():
return usage

if __name__ == '__main__':
if len(sys.argv) != 2:
if len(sys.argv) < 2: # If there's less than two arguments, the first being the name of the program, there can't possibly be a command
print usage()
sys.exit(-1)

context = zmq.Context()
cli_sock = context.socket(zmq.REQ)
cli_sock.connect("ipc://RPL_CLI")

try:
cli_sock.send(sys.argv[1], zmq.DONTWAIT)
except zmq.ZMQError, err:
print "unable to communicate with the simpleRPL daemon: %s" % err
sys.exit(-1)
print cli_sock.recv()
interactive = False

if sys.argv[1] == '-i': # Interactive mode is requested
interactive = True
else:
try:
cli_sock.send(sys.argv[1], zmq.DONTWAIT)
except zmq.ZMQError, err:
print "unable to communicate with the simpleRPL daemon: %s" % err
sys.exit(-1)
print cli_sock.recv()


while interactive:
command = raw_input("cliRPL > ")
if command == 'exit':
interactive = False
break
try:
print command
cli_sock.send(command, zmq.DONTWAIT)
except zmq.ZMQError, err:
print "unable to communicate with the simpleRPL daemon: %s" % err
sys.exit(-1)
print cli_sock.recv()